(-x^2+2x+8)-(2x-8)=0

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Solution for (-x^2+2x+8)-(2x-8)=0 equation:


Simplifying
(-1x2 + 2x + 8) + -1(2x + -8) = 0

Reorder the terms:
(8 + 2x + -1x2) + -1(2x + -8) = 0

Remove parenthesis around (8 + 2x + -1x2)
8 + 2x + -1x2 + -1(2x + -8) = 0

Reorder the terms:
8 + 2x + -1x2 + -1(-8 + 2x) = 0
8 + 2x + -1x2 + (-8 * -1 + 2x * -1) = 0
8 + 2x + -1x2 + (8 + -2x) = 0

Reorder the terms:
8 + 8 + 2x + -2x + -1x2 = 0

Combine like terms: 8 + 8 = 16
16 + 2x + -2x + -1x2 = 0

Combine like terms: 2x + -2x = 0
16 + 0 + -1x2 = 0
16 + -1x2 = 0

Solving
16 + -1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16' to each side of the equation.
16 + -16 + -1x2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + -1x2 = 0 + -16
-1x2 = 0 + -16

Combine like terms: 0 + -16 = -16
-1x2 = -16

Divide each side by '-1'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}

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